(3x-1)(9x^2-3x+1)=0

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Solution for (3x-1)(9x^2-3x+1)=0 equation:


Simplifying
(3x + -1)(9x2 + -3x + 1) = 0

Reorder the terms:
(-1 + 3x)(9x2 + -3x + 1) = 0

Reorder the terms:
(-1 + 3x)(1 + -3x + 9x2) = 0

Multiply (-1 + 3x) * (1 + -3x + 9x2)
(-1(1 + -3x + 9x2) + 3x * (1 + -3x + 9x2)) = 0
((1 * -1 + -3x * -1 + 9x2 * -1) + 3x * (1 + -3x + 9x2)) = 0
((-1 + 3x + -9x2) + 3x * (1 + -3x + 9x2)) = 0
(-1 + 3x + -9x2 + (1 * 3x + -3x * 3x + 9x2 * 3x)) = 0
(-1 + 3x + -9x2 + (3x + -9x2 + 27x3)) = 0

Reorder the terms:
(-1 + 3x + 3x + -9x2 + -9x2 + 27x3) = 0

Combine like terms: 3x + 3x = 6x
(-1 + 6x + -9x2 + -9x2 + 27x3) = 0

Combine like terms: -9x2 + -9x2 = -18x2
(-1 + 6x + -18x2 + 27x3) = 0

Solving
-1 + 6x + -18x2 + 27x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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